## NCERT MATHS SOLUTION CLASS 6 EXERCISE 7.3 CHAPTER 7 FRACTIONS

Find here, the step-by-step NCERT Maths Solution Class 6 Exercise 7.3 of Chapter 7 from CBSE Class 6 NCERT textbook.

Before moving to maths solution class 6 exercise 7.3, it is advised to go through the following topics
• FRACTIONS
• Exercise 7.1
• Exercise 7.2

## NCERT Maths Solution Class 6 Exercise 7.3 | Fractions

Problems in Exercise 7.3 require the knowledge of Equivalent fractions and Simplest form of fractions.

Fractions which represent the same proportion of the whole with different numerators and denominators are said to be Equivalent Fractions. They are equal in their simplest form.

Simplest form of a fraction is such that its numerator and denominator have no common factors except one i.e., their HCF should be 1.

## EXERCISE 7.3EQUIVALENT FRACTIONS | SIMPLEST FORM OF A FRACTION

QUESTION 1

Write the fractions. Are all these fractions equivalent?

ANSWER

(i) (ii) QUESTION 2

Write the fractions and pair up the equivalent fractions from each row.

ANSWER

(a) (ii)

(b) (iv)

(c) (i)

(d) (v)

(e) (iii)

NCERT Maths Solution Class 6 Exercise 7.3

QUESTION 3

Replace in each of the following by the correct number.

(i) (ii) (iii) (iv) (v) ANSWER

(i) 28 (2×4 = 8, 7×4 = 28)

(ii) 16 (5×2 = 10, 8×2 = 16)

(iii) 12 (3×4 = 12, 5×4 = 20)

(iv) 20 (45÷3 = 15, 60÷3 = 20)

(i) 3 (18÷6 = 3, 24÷6 = 4)

QUESTION 4

Find the equivalent fraction of 3/5 having:

(i) denominator 20

(ii) numerator 8

(iii) denominator 30

(iv) numerator 27

ANSWER

(i) (ii) (iii) (iv) NCERT Maths Solution Class 6 Exercise 7.3

QUESTION 5

Find the equivalent fraction of 36/48 with

(i) numerator 9

(ii) denominator 4

ANSWER

(i) (ii) QUESTION 6

Check whether the given fractions are equivalent :

(i) (ii) (iii) ANSWER

(i) 5×54 = 270, 9×30 = 270
Since, 5×54 = 9×30 (cross product)
Therefore, given fractions are equivalent.

(ii) 3×50 = 150, 10×12 = 120
Since, 3×50 10×12 (cross product)
Therefore, given fractions are not equivalent.

(iii) 7×11 = 77, 5×13 = 65
Since, 7×11 5×13 (cross product)
Therefore, given fractions are not equivalent.

QUESTION 7

Reduce the following fractions into simplest form :

(i) (ii) (iii) (iv) (v) ANSWER

(i) HCF of 48 and 60 = 12

Dividing both numerator and denominator by 12 Therfore, Simplest form of (ii) HCF of 150 and 60 = 30

Dividing both numerator and denominator by 30 Therfore, Simplest form of (iii) HCF of 84 and 98 = 14

Dividing both numerator and denominator by 14 Therfore, Simplest form of (iv) HCF of 12 and 52 = 4

Dividing both numerator and denominator by 4 Therfore, Simplest form of (v) HCF of 7 and 28 = 7

Dividing both numerator and denominator by 7 Therfore, Simplest form of NCERT Maths Solution Class 6 Exercise 7.3

QUESTION 8

Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, sheelu used up 25 pencils and Jamaal used up 40 pencils. What fractions did each use up? Check if each has used up an equal fraction of her/his pencils?

ANSWER

Fraction of pencils used up by Ramesh Fraction of pencils used up by Sheelu Fraction of pencils used up by Jammal Hence, each has used up an equal fraction of her/his pencils.

QUESTION 9

Match the equivalent fractions and write two more for each.

(i) (a) (ii) (b) (iii) (c) (iv) (d) (v) (e) ANSWER

(i) (d)

(ii) (e)

(iii) (a)

(iv) (c)

(v) (b)

## NCERT SOLUTIONS CLASS 6 MATHS CHAPTER 7 FRACTIONS

Check NCERT Solutions of other exercises from Class 6 Maths Chapter 7 Fractions by clicking the links given below.

We hope NCERT Maths Solution Class 6 Exercise 7.3 has helped you understand how to find Equivalents and Simplest form of a Fraction.

Write in the comment section to report any error or any solution related queries from the exercise. [ NCERT Maths Solution Class 6 Exercise 7.3 ]