NCERT MATHS SOLUTION CLASS 7 EXERCISE 2.7 | FRACTIONS & DECIMALS

Find here step-by-step NCERT Maths Solution Class 7 Exercise 2.7 of Chapter 2 Fractions and Decimals from CBSE NCERT textbook.

Before moving to maths solution class 7 exercise 2.7 , it is advised to go through the following topics
• Decimals
• Multiplication & Division of Decimals

NCERT Maths Solution Class 7 Exercise 2.7 | Fractions and Decimals

Problems in Exercise 2.7 require the knowledge of Decimals and their division.

While dividing two decimal numbers, first shift the decimal point to the right by equal number of places in both, to convert them to a whole number. Then divide.

EXERCISE 2.7

Division of Decimals

QUESTION 1

Find:

(i) 0.4 ÷ 2 (ii) 0.35 ÷ 5 (iii) 2.48 ÷ 4

(iv) 65.4 ÷ 6 (v) 651.2 ÷ 4 (vi) 14.49 ÷ 7

(vii) 3.96 ÷ 4 (viii) 0.80 ÷ 5

ANSWER

(i) 0.4 ÷ 2 =\frac{4}{20}=\frac{2}{10}= 0.2

(ii) 0.35 ÷ 5 =\frac{35}{500}=\frac{7}{100}= 0.07

(iii) 2.48 ÷ 4 =\frac{248}{400}=\frac{62}{100}= 0.62

(iv) 65.4 ÷ 6 =\frac{654}{60}=\frac{109}{10}= 10.9

(v) 651.2 ÷ 4 =\frac{6512}{40}=\frac{1628}{10}= 162.8

(vi) 14.49 ÷ 7 =\frac{1449}{700}=\frac{207}{100}= 2.07

(vii) 3.96 ÷ 4 =\frac{396}{400}=\frac{99}{100}= 0.99

(viii) 0.80 ÷ 5 =\frac{80}{500}=\frac{16}{100}= 0.16


ℹ️ While dividing a number by 10, 100 or 1000, the digits of the number and the quotient are same but the decimal point in the quotient shifts to the left by as many places as there are zeros over 1.

[ NCERT Maths Solution Class 7 Exercise 2.7 ]


QUESTION 2

Find:

(i) 4.8 ÷ 10 (ii) 52.5 ÷ 10

(iii) 0.7 ÷ 10 (iv) 33.1 ÷ 10

(v) 272.23 ÷ 10 (vi) 0.56 ÷ 10

(vii) 3.97 ÷10

ANSWER

(i) 4.8 ÷ 10 = 0.48
(ii) 52.5 ÷ 10 = 5.25

(iii) 0.7 ÷ 10 = 0.07
(iv) 33.1 ÷ 10 = 3.31

(v) 272.23 ÷ 10 = 27.223
(vi) 0.56 ÷ 10 = 0.056

(vii) 3.97 ÷10 = 0.397

QUESTION 3

Find:

(i) 2.7 ÷ 100 (ii) 0.3 ÷ 100

(iii) 0.78 ÷ 100 (iv) 432.6 ÷ 100

(v) 23.6 ÷100 (vi) 98.53 ÷ 100

ANSWER

(i) 2.7 ÷ 100 = 0.027
(ii) 0.3 ÷ 100 = 0.003

(iii) 0.78 ÷ 100 = 0.0078
(iv) 432.6 ÷ 100 = 4.326

(v) 23.6 ÷100 = 0.236
(vi) 98.53 ÷ 100 = 0.9853

[ NCERT Maths Solution Class 7 Exercise 2.7 ]

QUESTION 4

Find:

(i) 7.9 ÷ 1000 (ii) 26.3 ÷ 1000

(iii) 38.53 ÷ 1000 (iv) 128.9 ÷ 1000

(v) 0.5 ÷ 1000

ANSWER

(i) 7.9 ÷ 1000 = 0.0079
(ii) 26.3 ÷ 1000 = 0.0263

(iii) 38.53 ÷ 1000 = 0.03853
(iv) 128.9 ÷ 1000 = 0.1289

(v) 0.5 ÷ 1000 = 0.0005

QUESTION 5

Find:

(i) 7 ÷ 3.5 (ii) 36 ÷ 0.2

(iii) 3.25 ÷ 0.5 (iv) 30.94 ÷ 0.7

(v) 0.5 ÷ 0.25 (vi) 7.75 ÷ 0.25

(vii) 76.5 ÷ 0.15 (viii) 37.8 ÷ 1.4

(ix) 2.73 ÷ 1.3

ANSWER

(i) 7 ÷ 3.5 =\frac{70}{35}= 20

(ii) 36 ÷ 0.2 =\frac{360}{2}= 180

(iii) 3.25 ÷ 0.5 =\frac{325}{50}=\frac{65}{10}= 6.5

(iv) 30.94 ÷ 0.7 =\frac{3094}{70}=\frac{442}{10}= 44.2

(v) 0.5 ÷ 0.25 =\frac{50}{25}= 2

(vi) 7.75 ÷ 0.25 =\frac{775}{25}= 31

(vii) 76.5 ÷ 0.15 =\frac{7650}{15}= 5.1

(viii) 37.8 ÷ 1.4 =\frac{378}{14}= 2.7

(ix) 2.73 ÷ 1.3 =\frac{273}{130}=\frac{21}{10}= 2.1

[ NCERT Maths Solution Class 7 Exercise 2.7 ]

QUESTION 6

A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of

ANSWER

A vehicle covers a distance of 43.2 km in 2.4 litres of petrol.

Then, distance it will cover in one litre of petrol = 43.2 ÷ 2.4 km

=\frac{432}{24}=18 km

NCERT MATHS SOLUTION | CLASS 7 | CHAPTER 2 | FRACTIONS & DECIMALS

Exercise 2.1 | Exercise 2.2 | Exercise 2.3

Exercise 2.4 | Exercise 2.5 | Exercise 2.6

Exercise 2.7

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