## NCERT SOLUTIONS FOR CLASS 6 MATHS EXERCISE 10.3

Find here step by step NCERT Solutions for Class 6 Maths Exercise 10.3 Chapter 10 Mensuration. NCERT Solutions for Class 6 Maths Exercise 10.3 deals with the calculation of Area of Rectangles and Squares using formula.

> Area of a rectangle = length × breadth
> Area of a square = side × side

## Exercise – 10.3

QUESTION 1

Find the areas of the rectangles whose sides are :

(a) 3 cm and 4 cm (b) 12 m and 21 m
(c) 2 km and 3 km (d) 2 m and 70 cm

(a) Area of the rectangle = l×b
= 3 cm × 4 cm = 12

(b) Area of the rectangle = l×b
12 m × 21 m = 252

(c) Area of the rectangle = l×b
= 2 km × 3 km = 6

(d) Area of the rectangle = l×b
= 2 m × 70 cm = 2 m × 0.70 m = 1.40

QUESTION 2

Find the areas of the squares whose sides are :

(a) 10 cm (b) 14 cm (c) 5 m

(a) Area of the square = s×s
= 10 cm × 10 cm = 100

(b) Area of the square = s×s
= 14 cm × 14 cm = 196

(c) Area of the square = s×s
= 5 m × 5 m = 25

QUESTION 3

The length and breadth of three rectangles are as given below :

(a) 9 m and 6 m (b) 17 m and 3 m
(c) 4 m and 14 m.

Which one has the largest area and which one has the smallest?

(a) Area of the rectangle = 9 m × 6 m
= 54

(b) Area of the rectangle = 17 m × 3 m
= 51

(c) Area of the rectangle = 4 m × 14 m
= 56

Since, 56 > 54 > 51 ,

Therefore, rectangle (c) has the largest area and rectangle (b) has the smallest area.

QUESTION 4

The area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.

Length of the rectangular garden = 50 m,

Area of the rectangular garden = Length × Breadth = 300 ,

=> 50 m × Breadth = 300
=> Breadth = 300 ÷ 50 m = 6 m

Therefore, the width of the rectangular garden = 6 m.

QUESTION 5

What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of ₹ 8 per hundred sq m.?

Length of the rectangular plot = 500 m,

Width of the rectangular plot = 200 m,

So, area of the plot = 500 m × 200 m = 100,000

Now, rate of tiling = ₹ 8 per

Therefore, cost of tiling the plot = ₹ 8 per × 100,000
= ₹ 800,000.

QUESTION 6

A table-top measures 2 m by 1 m 50 cm. What is its area in square metres?

Length of the table top = 2 m,
Breadth of the table top = 1 m 50 cm = 1.50 m,

Therefore, area of the table top = 2 m × 1.50 m
= 3 .

QUESTION 7

A room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room?

Length of the room = 4 m,

Breadth of the room = 3 m 50 cm = 3.50 m,

So, area of the floor of the room = 4 m × 3.50 m
= 14 ,

Therefore, 14 of carpet is needed to cover the floor of the room.

QUESTION 8

A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.

Length of the floor = 5 m,

Breadth of the floor = 4 m,

So, area of the floor = 5 m × 4 m
= 20 ,

Side of the square carpet = 3 m,

So, area of the carpet = 3 m × 3 m
= 9

Now, area of the floor – area of the carpet = 20 – 9
= 11

Therefore, 11 of the floor is not carpeted.

QUESTION 9

Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

Side of the square flower beds = 1 m,

Area of the flower beds = 1 m × 1 m
= 1 ,

Total area of the flower beds = 5 × 1
= 5

Length of the land = 5 m,
and width of the land = 4 m,

So, area of the land = 5 m × 4 m
= 20 ,

Now, area of the land – area of the beds = 20 – 5
= 15

Therefore, area of the remaining part of the land = 15 .

QUESTION 10

By splitting the following figures into rectangles, find their areas (The measures are given in centimetres).

(a) Area of the figure = sum of the area of rectangles (a), (b), (c) and (d)

= ar(a) + ar(b) + ar(c) + ar(d)
= 4×3 + 2×1 + 3×2 + 4×2
= 12 + 2 + 6 + 8
= 28

(b) Area of the figure = sum of the area of rectangles (a), (b) and (c)

= ar(a) + ar(b) + ar(c) + ar(d)
= 3×1 + 3×1 + 3×1
= 3 + 3 + 3
= 9

QUESTION 11

Split the following shapes into rectangles and find their areas. (The measures are given in centimetres)

(a) Area of the figure = sum of the area of rectangles (a) and (b)

= ar(a) + ar(b)
= 12×2 + 8×2
= 24 + 16
= 40

(b) Area of the figure = sum of the area of rectangles (a), (b) and (c)

= ar(a) + ar(b) + ar(c) + ar(d)
= 7×7 + 21×7 + 7×7
= 49 + 147 + 49
= 245

(c) Area of the figure = sum of the area of rectangles (a) and (b)

= ar(a) + ar(b) + ar(c) + ar(d)
= 5×1 + 4×1
= 5 + 4
= 9

QUESTION 12

How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:

(a) 100 cm and 144 cm
(b) 70 cm and 36 cm.

Length of the tiles = 12 cm,
Breadth of the tiles = 5 cm,

So, area of the tiles = 12 cm × 5 cm
= 60

(a) Length of the rectangular region = 100 cm,
Breadth of the rectangular region = 144 cm,

So, area of the region = 100 cm × 144 cm
= 14,400

Therefore, number of tiles needed to fit the region = 14,400 ÷ 60
= 240

(b) Length of the rectangular region = 70 cm,
Breadth of the rectangular region = 36 cm,

So, area of the region = 70 cm × 36 cm

Therefore, number of tiles needed to fit the region = 70 cm × 36 cm ÷ 60
= 42

## NCERT SOLUTIONS CLASS 6 MATHS CHAPTER 10 Mensuration

Check NCERT Solutions of other exercises from Class 6 Maths Chapter 10 Mensuration by clicking the links given below.

We hope NCERT Solutions for Class 6 Maths Exercise 10.3 has helped you understand how to find area of rectangles and squares using formula.

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